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https://math.answers.com/math-and-arithmetic/How_do_you_solve_the_trigonomic_equation_sin2x_equals_negative_cosx

How do you solve the trigonomic equation sin2x equals negative cosx? - Answers

Sin(2x) = -cos(x)But sin(2x) = 2 sin(x) cos(x)Substitute it:2 sin(x) cos(x) = -cos(x)Divide each side by cos(x):2 sin(x) = -1sin(x) = -1/2x = 210°x = 330°



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How do you solve the trigonomic equation sin2x equals negative cosx? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_the_trigonomic_equation_sin2x_equals_negative_cosx

Sin(2x) = -cos(x)But sin(2x) = 2 sin(x) cos(x)Substitute it:2 sin(x) cos(x) = -cos(x)Divide each side by cos(x):2 sin(x) = -1sin(x) = -1/2x = 210°x = 330°



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_the_trigonomic_equation_sin2x_equals_negative_cosx

How do you solve the trigonomic equation sin2x equals negative cosx? - Answers

Sin(2x) = -cos(x)But sin(2x) = 2 sin(x) cos(x)Substitute it:2 sin(x) cos(x) = -cos(x)Divide each side by cos(x):2 sin(x) = -1sin(x) = -1/2x = 210°x = 330°

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      Sin(2x) = -cos(x)But sin(2x) = 2 sin(x) cos(x)Substitute it:2 sin(x) cos(x) = -cos(x)Divide each side by cos(x):2 sin(x) = -1sin(x) = -1/2x = 210°x = 330°

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