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How do you solve x³-4x equals 0 algebraically? - Answers

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.



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How do you solve x³-4x equals 0 algebraically? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_x%C2%B3-4x_equals_0_algebraically

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_x%C2%B3-4x_equals_0_algebraically

How do you solve x³-4x equals 0 algebraically? - Answers

Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

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      Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.

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