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How do you solve x2 equals 7-4? - Answers

If you actually meant that as you wrote it:x2 = 7 - 4Then the answer is simple:x2 = 7 - 4∴ x2 = 3∴ x = √3If on the other hand, you actually wanted to say:x2 = 7x - 4Then you can find it this way:x2 = 7x - 4∴ x - 7x = -4∴ x - 7x + (7/2)2 = -4 + (7/2)2∴ (x - 7/2)2 = -16/4 + 49/4∴ x - 7/2 = ± √(33/4)∴ x = 7/2 ± √33/2∴ x = (7 ± √33) / 2Alternatively, if you meant to say:x2 = 7 - 4xThen the answer is:x2 = 7 - 4x∴ x2 + 4x = 7∴ x2 + 4x + 4 = 7∴ (x + 2)2 = 7∴ x + 2 = ± √7∴ x = -2 ± √7



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How do you solve x2 equals 7-4? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_x2_equals_7-4

If you actually meant that as you wrote it:x2 = 7 - 4Then the answer is simple:x2 = 7 - 4∴ x2 = 3∴ x = √3If on the other hand, you actually wanted to say:x2 = 7x - 4Then you can find it this way:x2 = 7x - 4∴ x - 7x = -4∴ x - 7x + (7/2)2 = -4 + (7/2)2∴ (x - 7/2)2 = -16/4 + 49/4∴ x - 7/2 = ± √(33/4)∴ x = 7/2 ± √33/2∴ x = (7 ± √33) / 2Alternatively, if you meant to say:x2 = 7 - 4xThen the answer is:x2 = 7 - 4x∴ x2 + 4x = 7∴ x2 + 4x + 4 = 7∴ (x + 2)2 = 7∴ x + 2 = ± √7∴ x = -2 ± √7



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https://math.answers.com/math-and-arithmetic/How_do_you_solve_x2_equals_7-4

How do you solve x2 equals 7-4? - Answers

If you actually meant that as you wrote it:x2 = 7 - 4Then the answer is simple:x2 = 7 - 4∴ x2 = 3∴ x = √3If on the other hand, you actually wanted to say:x2 = 7x - 4Then you can find it this way:x2 = 7x - 4∴ x - 7x = -4∴ x - 7x + (7/2)2 = -4 + (7/2)2∴ (x - 7/2)2 = -16/4 + 49/4∴ x - 7/2 = ± √(33/4)∴ x = 7/2 ± √33/2∴ x = (7 ± √33) / 2Alternatively, if you meant to say:x2 = 7 - 4xThen the answer is:x2 = 7 - 4x∴ x2 + 4x = 7∴ x2 + 4x + 4 = 7∴ (x + 2)2 = 7∴ x + 2 = ± √7∴ x = -2 ± √7

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      If you actually meant that as you wrote it:x2 = 7 - 4Then the answer is simple:x2 = 7 - 4∴ x2 = 3∴ x = √3If on the other hand, you actually wanted to say:x2 = 7x - 4Then you can find it this way:x2 = 7x - 4∴ x - 7x = -4∴ x - 7x + (7/2)2 = -4 + (7/2)2∴ (x - 7/2)2 = -16/4 + 49/4∴ x - 7/2 = ± √(33/4)∴ x = 7/2 ± √33/2∴ x = (7 ± √33) / 2Alternatively, if you meant to say:x2 = 7 - 4xThen the answer is:x2 = 7 - 4x∴ x2 + 4x = 7∴ x2 + 4x + 4 = 7∴ (x + 2)2 = 7∴ x + 2 = ± √7∴ x = -2 ± √7

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