math.answers.com/math-and-arithmetic/How_do_you_solve_x4-6x2-12

Preview meta tags from the math.answers.com website.

Linked Hostnames

9

Thumbnail

Search Engine Appearance

Google

https://math.answers.com/math-and-arithmetic/How_do_you_solve_x4-6x2-12

How do you solve x4-6x2-12? - Answers

To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).



Bing

How do you solve x4-6x2-12? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_solve_x4-6x2-12

To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).



DuckDuckGo

https://math.answers.com/math-and-arithmetic/How_do_you_solve_x4-6x2-12

How do you solve x4-6x2-12? - Answers

To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).

  • General Meta Tags

    22
    • title
      How do you solve x4-6x2-12? - Answers
    • charset
      utf-8
    • Content-Type
      text/html; charset=utf-8
    • viewport
      minimum-scale=1, initial-scale=1, width=device-width, shrink-to-fit=no
    • X-UA-Compatible
      IE=edge,chrome=1

  • Open Graph Meta Tags

    7
    • og:image
      https://st.answers.com/html_test_assets/Answers_Blue.jpeg
    • og:image:width
      900
    • og:image:height
      900
    • og:site_name
      Answers
    • og:description
      To solve the equation ( x^4 - 6x^2 - 12 = 0 ), you can make a substitution by letting ( y = x^2 ). The equation then becomes ( y^2 - 6y - 12 = 0 ). You can solve this quadratic equation using the quadratic formula ( y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} ). After finding the values of ( y ), substitute back ( y = x^2 ) to find the values of ( x ).

  • Twitter Meta Tags

    1
    • twitter:card
      summary_large_image

  • Link Tags

    16
    • alternate
      https://www.answers.com/feed.rss
    • apple-touch-icon
      /icons/180x180.png
    • canonical
      https://math.answers.com/math-and-arithmetic/How_do_you_solve_x4-6x2-12
    • icon
      /favicon.svg
    • icon
      /icons/16x16.png

Links

59