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How do you subtract and reduce unlike fractions? - Answers

For example, you have 2/3 and 4/5 Fractions have this funny property: 2/3= 2*2/3*2= 2*3/3*3=2*4/3*4=2*a/3*a and so, we can fina a "common factor" between two numerators( in this case 3 and 5) so that you can muiltiply both side by a number which can make the fractions "alike" In this case, what number is divisible for both 3 and 5. THe easiest way is 3*5=15. So we have: 2/3=2*5/3*5=10/15 (this fraction is still the same with 2/3) and 4*3/5*3=12/15(again this is the same as 4/5) so we have the sum between them are: 2/3 + 4/5 = 10/15 + 12/15 = 22/15



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How do you subtract and reduce unlike fractions? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_subtract_and_reduce_unlike_fractions

For example, you have 2/3 and 4/5 Fractions have this funny property: 2/3= 2*2/3*2= 2*3/3*3=2*4/3*4=2*a/3*a and so, we can fina a "common factor" between two numerators( in this case 3 and 5) so that you can muiltiply both side by a number which can make the fractions "alike" In this case, what number is divisible for both 3 and 5. THe easiest way is 3*5=15. So we have: 2/3=2*5/3*5=10/15 (this fraction is still the same with 2/3) and 4*3/5*3=12/15(again this is the same as 4/5) so we have the sum between them are: 2/3 + 4/5 = 10/15 + 12/15 = 22/15



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https://math.answers.com/math-and-arithmetic/How_do_you_subtract_and_reduce_unlike_fractions

How do you subtract and reduce unlike fractions? - Answers

For example, you have 2/3 and 4/5 Fractions have this funny property: 2/3= 2*2/3*2= 2*3/3*3=2*4/3*4=2*a/3*a and so, we can fina a "common factor" between two numerators( in this case 3 and 5) so that you can muiltiply both side by a number which can make the fractions "alike" In this case, what number is divisible for both 3 and 5. THe easiest way is 3*5=15. So we have: 2/3=2*5/3*5=10/15 (this fraction is still the same with 2/3) and 4*3/5*3=12/15(again this is the same as 4/5) so we have the sum between them are: 2/3 + 4/5 = 10/15 + 12/15 = 22/15

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      For example, you have 2/3 and 4/5 Fractions have this funny property: 2/3= 2*2/3*2= 2*3/3*3=2*4/3*4=2*a/3*a and so, we can fina a "common factor" between two numerators( in this case 3 and 5) so that you can muiltiply both side by a number which can make the fractions "alike" In this case, what number is divisible for both 3 and 5. THe easiest way is 3*5=15. So we have: 2/3=2*5/3*5=10/15 (this fraction is still the same with 2/3) and 4*3/5*3=12/15(again this is the same as 4/5) so we have the sum between them are: 2/3 + 4/5 = 10/15 + 12/15 = 22/15

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