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https://math.answers.com/math-and-arithmetic/How_do_you_trisect_a_square_into_3_using_a_triangle

How do you trisect a square into 3 using a triangle? - Answers

The Triangle must have a base the dimension of the side of the square, the hypotenuse must also be the same length as the side of the square. Then lay the triangle onto the square so the base is exactly over one side of the square and the opposing point is touching the squares opposite side. The triangle covers 1 of the segments of the square and the uncovered parts make up the other 2. Am I even close?



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How do you trisect a square into 3 using a triangle? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_trisect_a_square_into_3_using_a_triangle

The Triangle must have a base the dimension of the side of the square, the hypotenuse must also be the same length as the side of the square. Then lay the triangle onto the square so the base is exactly over one side of the square and the opposing point is touching the squares opposite side. The triangle covers 1 of the segments of the square and the uncovered parts make up the other 2. Am I even close?



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https://math.answers.com/math-and-arithmetic/How_do_you_trisect_a_square_into_3_using_a_triangle

How do you trisect a square into 3 using a triangle? - Answers

The Triangle must have a base the dimension of the side of the square, the hypotenuse must also be the same length as the side of the square. Then lay the triangle onto the square so the base is exactly over one side of the square and the opposing point is touching the squares opposite side. The triangle covers 1 of the segments of the square and the uncovered parts make up the other 2. Am I even close?

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      The Triangle must have a base the dimension of the side of the square, the hypotenuse must also be the same length as the side of the square. Then lay the triangle onto the square so the base is exactly over one side of the square and the opposing point is touching the squares opposite side. The triangle covers 1 of the segments of the square and the uncovered parts make up the other 2. Am I even close?

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