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How do you use 172.16.0.0 to create 6 subnets? - Answers

To create 6 subnets from the IP address 172.16.0.0, you need to determine how many bits to borrow from the host portion of the address. Since 2^3 = 8, borrowing 3 bits allows for 8 subnets, which is sufficient for your requirement of 6. This results in a subnet mask of 255.255.248.0 (or /21), providing each subnet with 2046 usable host addresses. The subnets would range from 172.16.0.0/21 to 172.16.7.0/21.



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How do you use 172.16.0.0 to create 6 subnets? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_use_172.16.0.0_to_create_6_subnets

To create 6 subnets from the IP address 172.16.0.0, you need to determine how many bits to borrow from the host portion of the address. Since 2^3 = 8, borrowing 3 bits allows for 8 subnets, which is sufficient for your requirement of 6. This results in a subnet mask of 255.255.248.0 (or /21), providing each subnet with 2046 usable host addresses. The subnets would range from 172.16.0.0/21 to 172.16.7.0/21.



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https://math.answers.com/math-and-arithmetic/How_do_you_use_172.16.0.0_to_create_6_subnets

How do you use 172.16.0.0 to create 6 subnets? - Answers

To create 6 subnets from the IP address 172.16.0.0, you need to determine how many bits to borrow from the host portion of the address. Since 2^3 = 8, borrowing 3 bits allows for 8 subnets, which is sufficient for your requirement of 6. This results in a subnet mask of 255.255.248.0 (or /21), providing each subnet with 2046 usable host addresses. The subnets would range from 172.16.0.0/21 to 172.16.7.0/21.

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      To create 6 subnets from the IP address 172.16.0.0, you need to determine how many bits to borrow from the host portion of the address. Since 2^3 = 8, borrowing 3 bits allows for 8 subnets, which is sufficient for your requirement of 6. This results in a subnet mask of 255.255.248.0 (or /21), providing each subnet with 2046 usable host addresses. The subnets would range from 172.16.0.0/21 to 172.16.7.0/21.

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