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How do you use differentiation in general? - Answers

By in general I assume that you mean without using first principles. For d/dx of any single term all you do is take the power down to the front and make a new power of the old power minus one: e.g. d/dx(x2) = 2x(2-1) = 2x d/dx(3x4) =4.3x(4-1) = 12x3 This also works for fractions and negative numbers: e.g. d/dx(0.5x-1) = -1 times 0.5x(-1-1) = -0.5x-2.



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How do you use differentiation in general? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_use_differentiation_in_general

By in general I assume that you mean without using first principles. For d/dx of any single term all you do is take the power down to the front and make a new power of the old power minus one: e.g. d/dx(x2) = 2x(2-1) = 2x d/dx(3x4) =4.3x(4-1) = 12x3 This also works for fractions and negative numbers: e.g. d/dx(0.5x-1) = -1 times 0.5x(-1-1) = -0.5x-2.



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https://math.answers.com/math-and-arithmetic/How_do_you_use_differentiation_in_general

How do you use differentiation in general? - Answers

By in general I assume that you mean without using first principles. For d/dx of any single term all you do is take the power down to the front and make a new power of the old power minus one: e.g. d/dx(x2) = 2x(2-1) = 2x d/dx(3x4) =4.3x(4-1) = 12x3 This also works for fractions and negative numbers: e.g. d/dx(0.5x-1) = -1 times 0.5x(-1-1) = -0.5x-2.

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      By in general I assume that you mean without using first principles. For d/dx of any single term all you do is take the power down to the front and make a new power of the old power minus one: e.g. d/dx(x2) = 2x(2-1) = 2x d/dx(3x4) =4.3x(4-1) = 12x3 This also works for fractions and negative numbers: e.g. d/dx(0.5x-1) = -1 times 0.5x(-1-1) = -0.5x-2.

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