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How do you work out a sequence that doubles? - Answers

To work out a sequence that doubles, start with an initial number, often referred to as the first term. Multiply that number by 2 to get the second term, and continue multiplying by 2 for each subsequent term. For example, starting with 1, the sequence would be 1, 2, 4, 8, 16, and so on. This pattern of doubling can be expressed mathematically as ( a_n = a_1 \times 2^{(n-1)} ), where ( a_n ) is the nth term and ( a_1 ) is the first term.



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How do you work out a sequence that doubles? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_work_out_a_sequence_that_doubles

To work out a sequence that doubles, start with an initial number, often referred to as the first term. Multiply that number by 2 to get the second term, and continue multiplying by 2 for each subsequent term. For example, starting with 1, the sequence would be 1, 2, 4, 8, 16, and so on. This pattern of doubling can be expressed mathematically as ( a_n = a_1 \times 2^{(n-1)} ), where ( a_n ) is the nth term and ( a_1 ) is the first term.



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https://math.answers.com/math-and-arithmetic/How_do_you_work_out_a_sequence_that_doubles

How do you work out a sequence that doubles? - Answers

To work out a sequence that doubles, start with an initial number, often referred to as the first term. Multiply that number by 2 to get the second term, and continue multiplying by 2 for each subsequent term. For example, starting with 1, the sequence would be 1, 2, 4, 8, 16, and so on. This pattern of doubling can be expressed mathematically as ( a_n = a_1 \times 2^{(n-1)} ), where ( a_n ) is the nth term and ( a_1 ) is the first term.

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      To work out a sequence that doubles, start with an initial number, often referred to as the first term. Multiply that number by 2 to get the second term, and continue multiplying by 2 for each subsequent term. For example, starting with 1, the sequence would be 1, 2, 4, 8, 16, and so on. This pattern of doubling can be expressed mathematically as ( a_n = a_1 \times 2^{(n-1)} ), where ( a_n ) is the nth term and ( a_1 ) is the first term.

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