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How do you work out that 1 equals 2 using algebra? - Answers

Let a=ba^2=aba^2+a^2=a^2+ab2a^2=a^2+ab2a^2-2ab=a^2+ab-2ab2a^2-2ab=a^2-ab2(a^2-ab)=1(a^2-ab)Cancelling (a^2-ab)Thus;2=1Improved Answer:-Let x = ySo x-y = 0And 2x-2y = 0Then it follows that 1x-1y = 2x-2yTherefore 1(x-y) = 2(x-y)Divide both sides by (x-y)Thus 1 = 2



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How do you work out that 1 equals 2 using algebra? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_work_out_that_1_equals_2_using_algebra

Let a=ba^2=aba^2+a^2=a^2+ab2a^2=a^2+ab2a^2-2ab=a^2+ab-2ab2a^2-2ab=a^2-ab2(a^2-ab)=1(a^2-ab)Cancelling (a^2-ab)Thus;2=1Improved Answer:-Let x = ySo x-y = 0And 2x-2y = 0Then it follows that 1x-1y = 2x-2yTherefore 1(x-y) = 2(x-y)Divide both sides by (x-y)Thus 1 = 2



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https://math.answers.com/math-and-arithmetic/How_do_you_work_out_that_1_equals_2_using_algebra

How do you work out that 1 equals 2 using algebra? - Answers

Let a=ba^2=aba^2+a^2=a^2+ab2a^2=a^2+ab2a^2-2ab=a^2+ab-2ab2a^2-2ab=a^2-ab2(a^2-ab)=1(a^2-ab)Cancelling (a^2-ab)Thus;2=1Improved Answer:-Let x = ySo x-y = 0And 2x-2y = 0Then it follows that 1x-1y = 2x-2yTherefore 1(x-y) = 2(x-y)Divide both sides by (x-y)Thus 1 = 2

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      Let a=ba^2=aba^2+a^2=a^2+ab2a^2=a^2+ab2a^2-2ab=a^2+ab-2ab2a^2-2ab=a^2-ab2(a^2-ab)=1(a^2-ab)Cancelling (a^2-ab)Thus;2=1Improved Answer:-Let x = ySo x-y = 0And 2x-2y = 0Then it follows that 1x-1y = 2x-2yTherefore 1(x-y) = 2(x-y)Divide both sides by (x-y)Thus 1 = 2

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