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How do you write f(x) (x 2)(x 6) in standard form? - Answers

To write ( f(x) = (x - 2)(x - 6) ) in standard form, you need to expand the expression. Distributing the terms, you get ( f(x) = x^2 - 6x - 2x + 12 ), which simplifies to ( f(x) = x^2 - 8x + 12 ). Thus, the standard form of the function is ( f(x) = x^2 - 8x + 12 ).



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How do you write f(x) (x 2)(x 6) in standard form? - Answers

https://math.answers.com/math-and-arithmetic/How_do_you_write_f(x)_(x_2)(x_6)_in_standard_form

To write ( f(x) = (x - 2)(x - 6) ) in standard form, you need to expand the expression. Distributing the terms, you get ( f(x) = x^2 - 6x - 2x + 12 ), which simplifies to ( f(x) = x^2 - 8x + 12 ). Thus, the standard form of the function is ( f(x) = x^2 - 8x + 12 ).



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https://math.answers.com/math-and-arithmetic/How_do_you_write_f(x)_(x_2)(x_6)_in_standard_form

How do you write f(x) (x 2)(x 6) in standard form? - Answers

To write ( f(x) = (x - 2)(x - 6) ) in standard form, you need to expand the expression. Distributing the terms, you get ( f(x) = x^2 - 6x - 2x + 12 ), which simplifies to ( f(x) = x^2 - 8x + 12 ). Thus, the standard form of the function is ( f(x) = x^2 - 8x + 12 ).

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      To write ( f(x) = (x - 2)(x - 6) ) in standard form, you need to expand the expression. Distributing the terms, you get ( f(x) = x^2 - 6x - 2x + 12 ), which simplifies to ( f(x) = x^2 - 8x + 12 ). Thus, the standard form of the function is ( f(x) = x^2 - 8x + 12 ).

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