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How does 0.99 recurring equal 1? - Answers

0.33 recurring is the decimal equivalent of one third Multiply both expressions by 3 and you have 0.99 recurring = 3/3 = 1 * * * * * That is rather a circular argument, because it begs the question why 0.33 recurring equal to a third. Instead, suppose f = 0.99.... multiply both sides by 10 10f = 9.99... and since both numbers are recurring there is a nine in the same position after the decimal point in both equations. Subtracting the first from the second gives: 9f = 9 Divide both sides by 9 and you have f = 1



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How does 0.99 recurring equal 1? - Answers

https://math.answers.com/math-and-arithmetic/How_does_0.99_recurring_equal_1

0.33 recurring is the decimal equivalent of one third Multiply both expressions by 3 and you have 0.99 recurring = 3/3 = 1 * * * * * That is rather a circular argument, because it begs the question why 0.33 recurring equal to a third. Instead, suppose f = 0.99.... multiply both sides by 10 10f = 9.99... and since both numbers are recurring there is a nine in the same position after the decimal point in both equations. Subtracting the first from the second gives: 9f = 9 Divide both sides by 9 and you have f = 1



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https://math.answers.com/math-and-arithmetic/How_does_0.99_recurring_equal_1

How does 0.99 recurring equal 1? - Answers

0.33 recurring is the decimal equivalent of one third Multiply both expressions by 3 and you have 0.99 recurring = 3/3 = 1 * * * * * That is rather a circular argument, because it begs the question why 0.33 recurring equal to a third. Instead, suppose f = 0.99.... multiply both sides by 10 10f = 9.99... and since both numbers are recurring there is a nine in the same position after the decimal point in both equations. Subtracting the first from the second gives: 9f = 9 Divide both sides by 9 and you have f = 1

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      0.33 recurring is the decimal equivalent of one third Multiply both expressions by 3 and you have 0.99 recurring = 3/3 = 1 * * * * * That is rather a circular argument, because it begs the question why 0.33 recurring equal to a third. Instead, suppose f = 0.99.... multiply both sides by 10 10f = 9.99... and since both numbers are recurring there is a nine in the same position after the decimal point in both equations. Subtracting the first from the second gives: 9f = 9 Divide both sides by 9 and you have f = 1

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