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https://math.answers.com/math-and-arithmetic/How_many_arrangements_can_be_made_with_the_letters_spineless

How many arrangements can be made with the letters spineless? - Answers

The word "spineless" has 9 letters, including 3 s's and 2 e's, so the number of distinct permutations of the letters is: 9!/(3!2!) = 30,240



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How many arrangements can be made with the letters spineless? - Answers

https://math.answers.com/math-and-arithmetic/How_many_arrangements_can_be_made_with_the_letters_spineless

The word "spineless" has 9 letters, including 3 s's and 2 e's, so the number of distinct permutations of the letters is: 9!/(3!2!) = 30,240



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https://math.answers.com/math-and-arithmetic/How_many_arrangements_can_be_made_with_the_letters_spineless

How many arrangements can be made with the letters spineless? - Answers

The word "spineless" has 9 letters, including 3 s's and 2 e's, so the number of distinct permutations of the letters is: 9!/(3!2!) = 30,240

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      The word "spineless" has 9 letters, including 3 s's and 2 e's, so the number of distinct permutations of the letters is: 9!/(3!2!) = 30,240

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