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How many different whole numbers are factors of 100? - Answers

Producing a list of factor pairs is the easiest way. 1 x 100 2 x 50 4 x 25 5 x 20 10 x 10 As 10 is duplicated then there are 9 different numbers that are factors of 100. If if it just a total number of factors that is required (rather than the values) then this can be obtained by stating the original number in terms of its prime factors. 100 = 22 x 52. Add 1 to each exponent and obtain the product : (2 + 1)(2 + 1) = 3 x 3 = 9 ......which confirms the answer given above.



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How many different whole numbers are factors of 100? - Answers

https://math.answers.com/math-and-arithmetic/How_many_different_whole_numbers_are_factors_of_100

Producing a list of factor pairs is the easiest way. 1 x 100 2 x 50 4 x 25 5 x 20 10 x 10 As 10 is duplicated then there are 9 different numbers that are factors of 100. If if it just a total number of factors that is required (rather than the values) then this can be obtained by stating the original number in terms of its prime factors. 100 = 22 x 52. Add 1 to each exponent and obtain the product : (2 + 1)(2 + 1) = 3 x 3 = 9 ......which confirms the answer given above.



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https://math.answers.com/math-and-arithmetic/How_many_different_whole_numbers_are_factors_of_100

How many different whole numbers are factors of 100? - Answers

Producing a list of factor pairs is the easiest way. 1 x 100 2 x 50 4 x 25 5 x 20 10 x 10 As 10 is duplicated then there are 9 different numbers that are factors of 100. If if it just a total number of factors that is required (rather than the values) then this can be obtained by stating the original number in terms of its prime factors. 100 = 22 x 52. Add 1 to each exponent and obtain the product : (2 + 1)(2 + 1) = 3 x 3 = 9 ......which confirms the answer given above.

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      Producing a list of factor pairs is the easiest way. 1 x 100 2 x 50 4 x 25 5 x 20 10 x 10 As 10 is duplicated then there are 9 different numbers that are factors of 100. If if it just a total number of factors that is required (rather than the values) then this can be obtained by stating the original number in terms of its prime factors. 100 = 22 x 52. Add 1 to each exponent and obtain the product : (2 + 1)(2 + 1) = 3 x 3 = 9 ......which confirms the answer given above.

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