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Is 211032 divisible by 4? - Answers
Yes. To check if a number is divisible by 4, if the last 2 digits (as a number) are divisible by 4, so is the original number. 32 = 4 x 8 so as 32 is divisible by 4, so is 211032. An alternative test for 4: add the last digit to twice the preceding digit, and if this sum is divisible by 4 so is the original number. This can be repeated until a single digit remains which must be 4 or 8 (to be divisible by 4) if the original number is divisible by 4. for 211032: 2 + 3x2 = 8 → [single digit 8 which] is divisible by 4, so 211032 is also divisible by 4.
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Is 211032 divisible by 4? - Answers
Yes. To check if a number is divisible by 4, if the last 2 digits (as a number) are divisible by 4, so is the original number. 32 = 4 x 8 so as 32 is divisible by 4, so is 211032. An alternative test for 4: add the last digit to twice the preceding digit, and if this sum is divisible by 4 so is the original number. This can be repeated until a single digit remains which must be 4 or 8 (to be divisible by 4) if the original number is divisible by 4. for 211032: 2 + 3x2 = 8 → [single digit 8 which] is divisible by 4, so 211032 is also divisible by 4.
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Is 211032 divisible by 4? - Answers
Yes. To check if a number is divisible by 4, if the last 2 digits (as a number) are divisible by 4, so is the original number. 32 = 4 x 8 so as 32 is divisible by 4, so is 211032. An alternative test for 4: add the last digit to twice the preceding digit, and if this sum is divisible by 4 so is the original number. This can be repeated until a single digit remains which must be 4 or 8 (to be divisible by 4) if the original number is divisible by 4. for 211032: 2 + 3x2 = 8 → [single digit 8 which] is divisible by 4, so 211032 is also divisible by 4.
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- og:descriptionYes. To check if a number is divisible by 4, if the last 2 digits (as a number) are divisible by 4, so is the original number. 32 = 4 x 8 so as 32 is divisible by 4, so is 211032. An alternative test for 4: add the last digit to twice the preceding digit, and if this sum is divisible by 4 so is the original number. This can be repeated until a single digit remains which must be 4 or 8 (to be divisible by 4) if the original number is divisible by 4. for 211032: 2 + 3x2 = 8 → [single digit 8 which] is divisible by 4, so 211032 is also divisible by 4.
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