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3 times x over the quantity x squared plus x? - Answers

3Another Answer:2I get 2 and here is why:3X / (x^2 + x) = 1[multiply "both sides" by (x^2 + x)]3X = x^2 + x[subtract 3X from both sides]0 = x^2 - 2X[divide both sides by X]0 = x - 2[add 2 to both sides]2 = x... DOUBLECHECK ...3X / (x^2 + x) = 1(3 x 2 ) / ( 2^2 + 2 ) = 16 / ( 4 + 2 ) = 16 / 6 = 1



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3 times x over the quantity x squared plus x? - Answers

https://math.answers.com/other-math/3_times_x_over_the_quantity_x_squared_plus_x

3Another Answer:2I get 2 and here is why:3X / (x^2 + x) = 1[multiply "both sides" by (x^2 + x)]3X = x^2 + x[subtract 3X from both sides]0 = x^2 - 2X[divide both sides by X]0 = x - 2[add 2 to both sides]2 = x... DOUBLECHECK ...3X / (x^2 + x) = 1(3 x 2 ) / ( 2^2 + 2 ) = 16 / ( 4 + 2 ) = 16 / 6 = 1



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https://math.answers.com/other-math/3_times_x_over_the_quantity_x_squared_plus_x

3 times x over the quantity x squared plus x? - Answers

3Another Answer:2I get 2 and here is why:3X / (x^2 + x) = 1[multiply "both sides" by (x^2 + x)]3X = x^2 + x[subtract 3X from both sides]0 = x^2 - 2X[divide both sides by X]0 = x - 2[add 2 to both sides]2 = x... DOUBLECHECK ...3X / (x^2 + x) = 1(3 x 2 ) / ( 2^2 + 2 ) = 16 / ( 4 + 2 ) = 16 / 6 = 1

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      3Another Answer:2I get 2 and here is why:3X / (x^2 + x) = 1[multiply "both sides" by (x^2 + x)]3X = x^2 + x[subtract 3X from both sides]0 = x^2 - 2X[divide both sides by X]0 = x - 2[add 2 to both sides]2 = x... DOUBLECHECK ...3X / (x^2 + x) = 1(3 x 2 ) / ( 2^2 + 2 ) = 16 / ( 4 + 2 ) = 16 / 6 = 1

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