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7 odd numbers equal 40? - Answers

I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40



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7 odd numbers equal 40? - Answers

https://math.answers.com/other-math/7_odd_numbers_equal_40

I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40



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https://math.answers.com/other-math/7_odd_numbers_equal_40

7 odd numbers equal 40? - Answers

I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40

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      I don't believe this is possible. The formula for an odd number is (2n+1) where n is any integer. So, for seven odd numbers added together... {a,b,c,d,e,f,g are the integers) (2a +1) + (2b +1) + ... + (2g+1) = 2(a+b+c+d+e+f+g) + 7 = 2(h) + 7 h is an integer 2h + 7 must be an odd number, thus it can't equal 40

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