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Can a regular polygon have interior angle measures of 100 degrees? - Answers

No. Suppose such a polygon has n sides. Then the sum of the interior angles is (n-2)*180 degrees. Since it is regular, each interior angle is (n-2)*180 / n degrees. Thus (n-2)*180 / n = 100 (n-2)*180 = 100*n 180n - 360 = 100n 80n = 360 n = 4.5 Sorry, but you cannot have a polygon with 4.5 sides!



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Can a regular polygon have interior angle measures of 100 degrees? - Answers

https://math.answers.com/other-math/Can_a_regular_polygon_have_interior_angle_measures_of_100_degrees

No. Suppose such a polygon has n sides. Then the sum of the interior angles is (n-2)*180 degrees. Since it is regular, each interior angle is (n-2)*180 / n degrees. Thus (n-2)*180 / n = 100 (n-2)*180 = 100*n 180n - 360 = 100n 80n = 360 n = 4.5 Sorry, but you cannot have a polygon with 4.5 sides!



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https://math.answers.com/other-math/Can_a_regular_polygon_have_interior_angle_measures_of_100_degrees

Can a regular polygon have interior angle measures of 100 degrees? - Answers

No. Suppose such a polygon has n sides. Then the sum of the interior angles is (n-2)*180 degrees. Since it is regular, each interior angle is (n-2)*180 / n degrees. Thus (n-2)*180 / n = 100 (n-2)*180 = 100*n 180n - 360 = 100n 80n = 360 n = 4.5 Sorry, but you cannot have a polygon with 4.5 sides!

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      No. Suppose such a polygon has n sides. Then the sum of the interior angles is (n-2)*180 degrees. Since it is regular, each interior angle is (n-2)*180 / n degrees. Thus (n-2)*180 / n = 100 (n-2)*180 = 100*n 180n - 360 = 100n 80n = 360 n = 4.5 Sorry, but you cannot have a polygon with 4.5 sides!

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