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Can you solve quadratic forms with algebraic numerical coefficients? - Answers

If ax2+bx+c=0, then x=(-b/2a)± [√(b2-4ac)]/2a



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If ax2+bx+c=0, then x=(-b/2a)± [√(b2-4ac)]/2a



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Can you solve quadratic forms with algebraic numerical coefficients? - Answers

If ax2+bx+c=0, then x=(-b/2a)± [√(b2-4ac)]/2a

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