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Find a number whose double exceeds its quarter by 7? - Answers

4: whose double is 8 and quarter is 1. If the missing number is x, then: 2x = x/4 + 7 Multiply throughout by 4: 8x = x + 28 Subtract x from both sides: 7x = 28 Divide throughout by 7: x = 4



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Find a number whose double exceeds its quarter by 7? - Answers

https://math.answers.com/other-math/Find_a_number_whose_double_exceeds_its_quarter_by_7

4: whose double is 8 and quarter is 1. If the missing number is x, then: 2x = x/4 + 7 Multiply throughout by 4: 8x = x + 28 Subtract x from both sides: 7x = 28 Divide throughout by 7: x = 4



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https://math.answers.com/other-math/Find_a_number_whose_double_exceeds_its_quarter_by_7

Find a number whose double exceeds its quarter by 7? - Answers

4: whose double is 8 and quarter is 1. If the missing number is x, then: 2x = x/4 + 7 Multiply throughout by 4: 8x = x + 28 Subtract x from both sides: 7x = 28 Divide throughout by 7: x = 4

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      4: whose double is 8 and quarter is 1. If the missing number is x, then: 2x = x/4 + 7 Multiply throughout by 4: 8x = x + 28 Subtract x from both sides: 7x = 28 Divide throughout by 7: x = 4

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