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https://math.answers.com/other-math/Find_the_distance_between_the_points_-4_15_and_8_-1

Find the distance between the points -4 15 and 8 -1? - Answers

The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (12) and a vertical distance y2-y1 (-16). The square root of the squares is sqrt [122 + (-16)2] = sqrt [144 + 256] = sq rt [400] = 20.



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Find the distance between the points -4 15 and 8 -1? - Answers

https://math.answers.com/other-math/Find_the_distance_between_the_points_-4_15_and_8_-1

The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (12) and a vertical distance y2-y1 (-16). The square root of the squares is sqrt [122 + (-16)2] = sqrt [144 + 256] = sq rt [400] = 20.



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https://math.answers.com/other-math/Find_the_distance_between_the_points_-4_15_and_8_-1

Find the distance between the points -4 15 and 8 -1? - Answers

The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (12) and a vertical distance y2-y1 (-16). The square root of the squares is sqrt [122 + (-16)2] = sqrt [144 + 256] = sq rt [400] = 20.

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      The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (12) and a vertical distance y2-y1 (-16). The square root of the squares is sqrt [122 + (-16)2] = sqrt [144 + 256] = sq rt [400] = 20.

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