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Find the range of f in fx-x2 -4x 5? - Answers

F(x) = -x^2 - 4x + 5 This is a quadratic function of the form y = ax + by + c, whose graph is a parabola. So, a = -1, b = -4 and c = 5 Since a is negative the parabola opens downward, and the maximum valy of the function is equal to the value of the y-coordinate of the vertex. The x- coordinate of the vertex is x = -b/2a. So, x = -(-4)/[2(-1) = 4/-2 = -2 When x = -2, then y = -(-2)^2 - 4(-2) + 5 = -4 + 8 + 5 = 9 Thus, the range is all value of y, such that y ≤ 9, Equivalently, the range is {y| y ≤ 9} or [9, ∞).



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Find the range of f in fx-x2 -4x 5? - Answers

https://math.answers.com/other-math/Find_the_range_of_f_in_fx-x2_-4x_5

F(x) = -x^2 - 4x + 5 This is a quadratic function of the form y = ax + by + c, whose graph is a parabola. So, a = -1, b = -4 and c = 5 Since a is negative the parabola opens downward, and the maximum valy of the function is equal to the value of the y-coordinate of the vertex. The x- coordinate of the vertex is x = -b/2a. So, x = -(-4)/[2(-1) = 4/-2 = -2 When x = -2, then y = -(-2)^2 - 4(-2) + 5 = -4 + 8 + 5 = 9 Thus, the range is all value of y, such that y ≤ 9, Equivalently, the range is {y| y ≤ 9} or [9, ∞).



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https://math.answers.com/other-math/Find_the_range_of_f_in_fx-x2_-4x_5

Find the range of f in fx-x2 -4x 5? - Answers

F(x) = -x^2 - 4x + 5 This is a quadratic function of the form y = ax + by + c, whose graph is a parabola. So, a = -1, b = -4 and c = 5 Since a is negative the parabola opens downward, and the maximum valy of the function is equal to the value of the y-coordinate of the vertex. The x- coordinate of the vertex is x = -b/2a. So, x = -(-4)/[2(-1) = 4/-2 = -2 When x = -2, then y = -(-2)^2 - 4(-2) + 5 = -4 + 8 + 5 = 9 Thus, the range is all value of y, such that y ≤ 9, Equivalently, the range is {y| y ≤ 9} or [9, ∞).

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      F(x) = -x^2 - 4x + 5 This is a quadratic function of the form y = ax + by + c, whose graph is a parabola. So, a = -1, b = -4 and c = 5 Since a is negative the parabola opens downward, and the maximum valy of the function is equal to the value of the y-coordinate of the vertex. The x- coordinate of the vertex is x = -b/2a. So, x = -(-4)/[2(-1) = 4/-2 = -2 When x = -2, then y = -(-2)^2 - 4(-2) + 5 = -4 + 8 + 5 = 9 Thus, the range is all value of y, such that y ≤ 9, Equivalently, the range is {y| y ≤ 9} or [9, ∞).

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