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https://math.answers.com/other-math/Find_the_y-intercepts_of_16y_squared_equals_120x-225

Find the y-intercepts of 16y squared equals 120x-225? - Answers

We are told: 16y2 = 120x - 225 The y-intercepts will happen where x equals zero, so we can say: 16y2 = 120(0) - 225 16y2 = -225 y2 = -225 / 16 y = √(-225 / 16) y = ±15i/4



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Find the y-intercepts of 16y squared equals 120x-225? - Answers

https://math.answers.com/other-math/Find_the_y-intercepts_of_16y_squared_equals_120x-225

We are told: 16y2 = 120x - 225 The y-intercepts will happen where x equals zero, so we can say: 16y2 = 120(0) - 225 16y2 = -225 y2 = -225 / 16 y = √(-225 / 16) y = ±15i/4



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https://math.answers.com/other-math/Find_the_y-intercepts_of_16y_squared_equals_120x-225

Find the y-intercepts of 16y squared equals 120x-225? - Answers

We are told: 16y2 = 120x - 225 The y-intercepts will happen where x equals zero, so we can say: 16y2 = 120(0) - 225 16y2 = -225 y2 = -225 / 16 y = √(-225 / 16) y = ±15i/4

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      We are told: 16y2 = 120x - 225 The y-intercepts will happen where x equals zero, so we can say: 16y2 = 120(0) - 225 16y2 = -225 y2 = -225 / 16 y = √(-225 / 16) y = ±15i/4

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