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https://math.answers.com/other-math/Graph_x-4y_equals_8

Graph x-4y equals 8? - Answers

First, rewrite the equation as a function of x:x - 4y = 84y = x - 8y = x/4 - 2So you know that this will be a line with a slope of 1/4. Now, find any two points on that line. The easiest way to do that is ~usually~ to solve for the points where x = 0 and where y = 0:y = 0/4 - 2y = -2So the point (0, -2) is on the line.0 = x/4 - 2x/4 = 2x = 8So the point (8, 0) is on the line.You can now graph this line with the following steps:grab a piece of graph paperdraw a y-axis vertically, and an x-axis horizontally, with enough room on the paper to draw those two pointsenumerate those axis, with point 0, 0 at the center, with the y axis incrementing positively upward, and the x axis incrementing positively to the rightplot those two points, (0, -2) and (8, 0)take a ruler and line it up with one of it's edges immediately beside both of those pointsdrag your pencil along that same edge of the ruler, through the full range of the graph.And that's all there is to it!



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Graph x-4y equals 8? - Answers

https://math.answers.com/other-math/Graph_x-4y_equals_8

First, rewrite the equation as a function of x:x - 4y = 84y = x - 8y = x/4 - 2So you know that this will be a line with a slope of 1/4. Now, find any two points on that line. The easiest way to do that is ~usually~ to solve for the points where x = 0 and where y = 0:y = 0/4 - 2y = -2So the point (0, -2) is on the line.0 = x/4 - 2x/4 = 2x = 8So the point (8, 0) is on the line.You can now graph this line with the following steps:grab a piece of graph paperdraw a y-axis vertically, and an x-axis horizontally, with enough room on the paper to draw those two pointsenumerate those axis, with point 0, 0 at the center, with the y axis incrementing positively upward, and the x axis incrementing positively to the rightplot those two points, (0, -2) and (8, 0)take a ruler and line it up with one of it's edges immediately beside both of those pointsdrag your pencil along that same edge of the ruler, through the full range of the graph.And that's all there is to it!



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https://math.answers.com/other-math/Graph_x-4y_equals_8

Graph x-4y equals 8? - Answers

First, rewrite the equation as a function of x:x - 4y = 84y = x - 8y = x/4 - 2So you know that this will be a line with a slope of 1/4. Now, find any two points on that line. The easiest way to do that is ~usually~ to solve for the points where x = 0 and where y = 0:y = 0/4 - 2y = -2So the point (0, -2) is on the line.0 = x/4 - 2x/4 = 2x = 8So the point (8, 0) is on the line.You can now graph this line with the following steps:grab a piece of graph paperdraw a y-axis vertically, and an x-axis horizontally, with enough room on the paper to draw those two pointsenumerate those axis, with point 0, 0 at the center, with the y axis incrementing positively upward, and the x axis incrementing positively to the rightplot those two points, (0, -2) and (8, 0)take a ruler and line it up with one of it's edges immediately beside both of those pointsdrag your pencil along that same edge of the ruler, through the full range of the graph.And that's all there is to it!

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      First, rewrite the equation as a function of x:x - 4y = 84y = x - 8y = x/4 - 2So you know that this will be a line with a slope of 1/4. Now, find any two points on that line. The easiest way to do that is ~usually~ to solve for the points where x = 0 and where y = 0:y = 0/4 - 2y = -2So the point (0, -2) is on the line.0 = x/4 - 2x/4 = 2x = 8So the point (8, 0) is on the line.You can now graph this line with the following steps:grab a piece of graph paperdraw a y-axis vertically, and an x-axis horizontally, with enough room on the paper to draw those two pointsenumerate those axis, with point 0, 0 at the center, with the y axis incrementing positively upward, and the x axis incrementing positively to the rightplot those two points, (0, -2) and (8, 0)take a ruler and line it up with one of it's edges immediately beside both of those pointsdrag your pencil along that same edge of the ruler, through the full range of the graph.And that's all there is to it!
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