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Graph x2-12y equals 0? - Answers

You have this equation: x2 - 12y = 0 First, move the term with y to the right side using addition: x2 = 12y Now, divide both sides by 12, so y is by itself: x2/12 = y From here, you can use the properties of a parabola (y = x2), "flattening" it so that it is 1/12 of the usual height. You can start with the fact that a parabola is symmetrical over the y-axis-- the vertical line through the point (0,0)-- and passes through the point (0,0). From that point, it gradually turns upward as it moves away from (0,0), passing through the points (1, 1/12), (2, 4/12), (3, 9/12), and so on.



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Graph x2-12y equals 0? - Answers

https://math.answers.com/other-math/Graph_x2-12y_equals_0

You have this equation: x2 - 12y = 0 First, move the term with y to the right side using addition: x2 = 12y Now, divide both sides by 12, so y is by itself: x2/12 = y From here, you can use the properties of a parabola (y = x2), "flattening" it so that it is 1/12 of the usual height. You can start with the fact that a parabola is symmetrical over the y-axis-- the vertical line through the point (0,0)-- and passes through the point (0,0). From that point, it gradually turns upward as it moves away from (0,0), passing through the points (1, 1/12), (2, 4/12), (3, 9/12), and so on.



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https://math.answers.com/other-math/Graph_x2-12y_equals_0

Graph x2-12y equals 0? - Answers

You have this equation: x2 - 12y = 0 First, move the term with y to the right side using addition: x2 = 12y Now, divide both sides by 12, so y is by itself: x2/12 = y From here, you can use the properties of a parabola (y = x2), "flattening" it so that it is 1/12 of the usual height. You can start with the fact that a parabola is symmetrical over the y-axis-- the vertical line through the point (0,0)-- and passes through the point (0,0). From that point, it gradually turns upward as it moves away from (0,0), passing through the points (1, 1/12), (2, 4/12), (3, 9/12), and so on.

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      You have this equation: x2 - 12y = 0 First, move the term with y to the right side using addition: x2 = 12y Now, divide both sides by 12, so y is by itself: x2/12 = y From here, you can use the properties of a parabola (y = x2), "flattening" it so that it is 1/12 of the usual height. You can start with the fact that a parabola is symmetrical over the y-axis-- the vertical line through the point (0,0)-- and passes through the point (0,0). From that point, it gradually turns upward as it moves away from (0,0), passing through the points (1, 1/12), (2, 4/12), (3, 9/12), and so on.
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