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How Do you find the nth term 15 12 9 6? - Answers

There are infinitely many formula that give the four terms {15, 12, 9, 6} for n = 1, 2, 3, 4; the way they continue after n=4 will be different.The nth term is given by:U{n} = (13n⁴ - 130n³ + 455n² - 674n + 456)/8Which makes U{5} = 42.However, I suspect that your teacher wants the much simpler formula for the Arithmetic Progression with the initial term of 15 and common difference of -3:U{n} = 18 - 3n



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How Do you find the nth term 15 12 9 6? - Answers

https://math.answers.com/other-math/How_Do_you_find_the_nth_term_15_12_9_6

There are infinitely many formula that give the four terms {15, 12, 9, 6} for n = 1, 2, 3, 4; the way they continue after n=4 will be different.The nth term is given by:U{n} = (13n⁴ - 130n³ + 455n² - 674n + 456)/8Which makes U{5} = 42.However, I suspect that your teacher wants the much simpler formula for the Arithmetic Progression with the initial term of 15 and common difference of -3:U{n} = 18 - 3n



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https://math.answers.com/other-math/How_Do_you_find_the_nth_term_15_12_9_6

How Do you find the nth term 15 12 9 6? - Answers

There are infinitely many formula that give the four terms {15, 12, 9, 6} for n = 1, 2, 3, 4; the way they continue after n=4 will be different.The nth term is given by:U{n} = (13n⁴ - 130n³ + 455n² - 674n + 456)/8Which makes U{5} = 42.However, I suspect that your teacher wants the much simpler formula for the Arithmetic Progression with the initial term of 15 and common difference of -3:U{n} = 18 - 3n

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      There are infinitely many formula that give the four terms {15, 12, 9, 6} for n = 1, 2, 3, 4; the way they continue after n=4 will be different.The nth term is given by:U{n} = (13n⁴ - 130n³ + 455n² - 674n + 456)/8Which makes U{5} = 42.However, I suspect that your teacher wants the much simpler formula for the Arithmetic Progression with the initial term of 15 and common difference of -3:U{n} = 18 - 3n

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