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How can you make 89 cents with 6 coins? - Answers

To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)



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How can you make 89 cents with 6 coins? - Answers

https://math.answers.com/other-math/How_can_you_make_89_cents_with_6_coins

To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)



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https://math.answers.com/other-math/How_can_you_make_89_cents_with_6_coins

How can you make 89 cents with 6 coins? - Answers

To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)

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      To make 89 cents with 6 coins, you have to first realize that the "9" part of the cents is comprised of 5 cents and 4 pennies. Therefore, you have to have 4 pennies and 85 cents using 2 coins; impossible, since you would need 3 coins(if you had half-dollars) to make that amount: a half-dollar, quarter, and a dime. Basically, it's impossible with only coins worth 0.01, 0.05, 0.10, 0.25, and 0.50 of the currency(US$, I assume?)

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