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https://math.answers.com/other-math/How_do_you_convert_a_pos_form_into_sop_form

How do you convert a pos form into sop form? - Answers

take the whole compliment, since POS is a dual to the SOP form,In the following we apply de-morgan's laws which are : (a+b)' = a' b' ; (ab)' = a' + b'(A'CD + E'F + BCD)'= (A'CD + E'F)' * (BCD)'= (A'CD)' * (E'F)' * (BCD)'= ((A')' + C' + D' ) * ( (E')' + F' ) * (B' + C' + D')= (A + C' + D' ) * ( E + F') * (B' + C' + D')which is the product of sums, that is POS form!



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How do you convert a pos form into sop form? - Answers

https://math.answers.com/other-math/How_do_you_convert_a_pos_form_into_sop_form

take the whole compliment, since POS is a dual to the SOP form,In the following we apply de-morgan's laws which are : (a+b)' = a' b' ; (ab)' = a' + b'(A'CD + E'F + BCD)'= (A'CD + E'F)' * (BCD)'= (A'CD)' * (E'F)' * (BCD)'= ((A')' + C' + D' ) * ( (E')' + F' ) * (B' + C' + D')= (A + C' + D' ) * ( E + F') * (B' + C' + D')which is the product of sums, that is POS form!



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https://math.answers.com/other-math/How_do_you_convert_a_pos_form_into_sop_form

How do you convert a pos form into sop form? - Answers

take the whole compliment, since POS is a dual to the SOP form,In the following we apply de-morgan's laws which are : (a+b)' = a' b' ; (ab)' = a' + b'(A'CD + E'F + BCD)'= (A'CD + E'F)' * (BCD)'= (A'CD)' * (E'F)' * (BCD)'= ((A')' + C' + D' ) * ( (E')' + F' ) * (B' + C' + D')= (A + C' + D' ) * ( E + F') * (B' + C' + D')which is the product of sums, that is POS form!

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      take the whole compliment, since POS is a dual to the SOP form,In the following we apply de-morgan's laws which are : (a+b)' = a' b' ; (ab)' = a' + b'(A'CD + E'F + BCD)'= (A'CD + E'F)' * (BCD)'= (A'CD)' * (E'F)' * (BCD)'= ((A')' + C' + D' ) * ( (E')' + F' ) * (B' + C' + D')= (A + C' + D' ) * ( E + F') * (B' + C' + D')which is the product of sums, that is POS form!

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