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How do you convert ppm in g per kwh? - Answers
PPM is a ratio, unitless: example (micro-litre/litre, or micro-mole/mole...ets) for simplicity the conversion is best understood with a simple example: if we are given the concentration of CO gas ( carbon monoxide) from an engine exhaust. brake power or rated power of the engine should be determined or be given, also mass flow rate of the exhaust gas shoulb be known or calculated: Now the conversion: 1- first determine molar mass of CO=12+16=28 grams/mol 2- determine the molar mass of air appx 29 kg/kmol = 29 g/mole 3- PPM (CO) = 4 (example) thus 4 micro-moles/ 1 mole **equivalent to 4*10^-6 mole / mole 4- { [(4*10^-6 mole/ mole)*( 28/29)* (mass flow)*(3600 sec/1hr)] / power } hope this helps.
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How do you convert ppm in g per kwh? - Answers
PPM is a ratio, unitless: example (micro-litre/litre, or micro-mole/mole...ets) for simplicity the conversion is best understood with a simple example: if we are given the concentration of CO gas ( carbon monoxide) from an engine exhaust. brake power or rated power of the engine should be determined or be given, also mass flow rate of the exhaust gas shoulb be known or calculated: Now the conversion: 1- first determine molar mass of CO=12+16=28 grams/mol 2- determine the molar mass of air appx 29 kg/kmol = 29 g/mole 3- PPM (CO) = 4 (example) thus 4 micro-moles/ 1 mole **equivalent to 4*10^-6 mole / mole 4- { [(4*10^-6 mole/ mole)*( 28/29)* (mass flow)*(3600 sec/1hr)] / power } hope this helps.
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How do you convert ppm in g per kwh? - Answers
PPM is a ratio, unitless: example (micro-litre/litre, or micro-mole/mole...ets) for simplicity the conversion is best understood with a simple example: if we are given the concentration of CO gas ( carbon monoxide) from an engine exhaust. brake power or rated power of the engine should be determined or be given, also mass flow rate of the exhaust gas shoulb be known or calculated: Now the conversion: 1- first determine molar mass of CO=12+16=28 grams/mol 2- determine the molar mass of air appx 29 kg/kmol = 29 g/mole 3- PPM (CO) = 4 (example) thus 4 micro-moles/ 1 mole **equivalent to 4*10^-6 mole / mole 4- { [(4*10^-6 mole/ mole)*( 28/29)* (mass flow)*(3600 sec/1hr)] / power } hope this helps.
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