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How do you determine if three points are collinear? - Answers

Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line



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How do you determine if three points are collinear? - Answers

https://math.answers.com/other-math/How_do_you_determine_if_three_points_are_collinear

Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line



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https://math.answers.com/other-math/How_do_you_determine_if_three_points_are_collinear

How do you determine if three points are collinear? - Answers

Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line

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      Since any 2 points determine 1 line, take 2 of the points and find the equation of the line drawn thru these 2 points. Substitute the x and y of the either point into the equation and find the y-intercept (b) Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are =. (y2-y1) ÷ (x2 - x1) = slope y = slope * x + b Point # 1 = (6, 5) Point # 2 = (10, 25) Point # 3 = (12, 30) Point # 4 = (12, 35) (y2 - y1) ÷ (x2 - x1) = slope (25 - 5) ÷ (10 - 6) = slope (20) ÷ (4) = slope Slope = 5 y = m * x + b y = 5 * x + b Substitute the x and y of the point (6, 5) into the equation and find the y-intercept (b) y = 5 * x + b 5 = 5 * 6 + b 5 = 30 + b b = -25 y = 5 * x - 25 . Check your points Point # 1 = (6, 5) 5 = 5 * 6 - 25 5 = 30 - 25 OK . Point # 2 = (10, 25) 25 = 5 * 10 - 25 25 = 5 * 10 - 25 OK . Then, substitute the x and y of the 3rd point into the equation and see if the both sides of the equation are Point # 3 = (12, 30) . y = 5 * x - 25 30 = 5 * 12 - 25 30 = 60 - 25 = 35 Point # 3 = (12, 30) is not on the line . . Point # 4 = (12, 35) 35 = 5 * 12 - 25 35 = 60 - 25 =35 Point # 4 = (12, 35) is on the line

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