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How do you factor 27x to the 3rd power - 8? - Answers

The basic formula for factoring the difference between two perfect cubes is (a3 - b3) = (a - b)(a2 + ab + b2). Substituting the given polynomial yields (27x3 - 8) = (3x - 2)(9x2 + 6x + 4).



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How do you factor 27x to the 3rd power - 8? - Answers

https://math.answers.com/other-math/How_do_you_factor_27x_to_the_3rd_power_-_8

The basic formula for factoring the difference between two perfect cubes is (a3 - b3) = (a - b)(a2 + ab + b2). Substituting the given polynomial yields (27x3 - 8) = (3x - 2)(9x2 + 6x + 4).



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https://math.answers.com/other-math/How_do_you_factor_27x_to_the_3rd_power_-_8

How do you factor 27x to the 3rd power - 8? - Answers

The basic formula for factoring the difference between two perfect cubes is (a3 - b3) = (a - b)(a2 + ab + b2). Substituting the given polynomial yields (27x3 - 8) = (3x - 2)(9x2 + 6x + 4).

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      The basic formula for factoring the difference between two perfect cubes is (a3 - b3) = (a - b)(a2 + ab + b2). Substituting the given polynomial yields (27x3 - 8) = (3x - 2)(9x2 + 6x + 4).

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