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https://math.answers.com/other-math/How_do_you_factor_the_trinomial_6x2_-_13x_-_63
How do you factor the trinomial 6x2 - 13x - 63? - Answers
6x2 - 13x - 63 = (2x - 9)(3x + 7). 6x2 - 13x - 63 since (6)(-63) = -(2*3*9*7) = (-27)(14),then -27 + 14 = -13, I write: = (6x - 27)(6x + 14)/3*2 = (2x - 9)(3x + 7)
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How do you factor the trinomial 6x2 - 13x - 63? - Answers
https://math.answers.com/other-math/How_do_you_factor_the_trinomial_6x2_-_13x_-_63
6x2 - 13x - 63 = (2x - 9)(3x + 7). 6x2 - 13x - 63 since (6)(-63) = -(2*3*9*7) = (-27)(14),then -27 + 14 = -13, I write: = (6x - 27)(6x + 14)/3*2 = (2x - 9)(3x + 7)
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How do you factor the trinomial 6x2 - 13x - 63? - Answers
6x2 - 13x - 63 = (2x - 9)(3x + 7). 6x2 - 13x - 63 since (6)(-63) = -(2*3*9*7) = (-27)(14),then -27 + 14 = -13, I write: = (6x - 27)(6x + 14)/3*2 = (2x - 9)(3x + 7)
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- og:description6x2 - 13x - 63 = (2x - 9)(3x + 7). 6x2 - 13x - 63 since (6)(-63) = -(2*3*9*7) = (-27)(14),then -27 + 14 = -13, I write: = (6x - 27)(6x + 14)/3*2 = (2x - 9)(3x + 7)
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