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How do you find five consecutive number whose sum is 465? - Answers

Let the number be represented by 'a' a+(a+1)+(a+2)+(a+3)+(a+4)=465 a+a+1+a+2+a+3+a+4=465 a+a+a+a+a+1+2+3+4=465 5a+10=465 5a=465-10 5a=455 5a/5=455/5 a=91 So if a=91 a+1=92 a+2=93 a+3=94 a+4=95



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How do you find five consecutive number whose sum is 465? - Answers

https://math.answers.com/other-math/How_do_you_find_five_consecutive_number_whose_sum_is_465

Let the number be represented by 'a' a+(a+1)+(a+2)+(a+3)+(a+4)=465 a+a+1+a+2+a+3+a+4=465 a+a+a+a+a+1+2+3+4=465 5a+10=465 5a=465-10 5a=455 5a/5=455/5 a=91 So if a=91 a+1=92 a+2=93 a+3=94 a+4=95



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https://math.answers.com/other-math/How_do_you_find_five_consecutive_number_whose_sum_is_465

How do you find five consecutive number whose sum is 465? - Answers

Let the number be represented by 'a' a+(a+1)+(a+2)+(a+3)+(a+4)=465 a+a+1+a+2+a+3+a+4=465 a+a+a+a+a+1+2+3+4=465 5a+10=465 5a=465-10 5a=455 5a/5=455/5 a=91 So if a=91 a+1=92 a+2=93 a+3=94 a+4=95

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      Let the number be represented by 'a' a+(a+1)+(a+2)+(a+3)+(a+4)=465 a+a+1+a+2+a+3+a+4=465 a+a+a+a+a+1+2+3+4=465 5a+10=465 5a=465-10 5a=455 5a/5=455/5 a=91 So if a=91 a+1=92 a+2=93 a+3=94 a+4=95
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