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https://math.answers.com/other-math/How_do_you_find_the_LCM_of_2_monomials

How do you find the LCM of 2 monomials? - Answers

This is similar to the often-used method to find the LCM of 2 numbers: you have to factor each monomial, and eliminate duplicate factors (factors that appear in both terms). An example might make this clearer. LCM of x2 + 5x, and x2 + 6x + 1 Factoring each: x(x+5), and (x+1)(x+5) Multiply all the factors, but use the common factor (x+5) only once: x(x+5)(x+1)



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How do you find the LCM of 2 monomials? - Answers

https://math.answers.com/other-math/How_do_you_find_the_LCM_of_2_monomials

This is similar to the often-used method to find the LCM of 2 numbers: you have to factor each monomial, and eliminate duplicate factors (factors that appear in both terms). An example might make this clearer. LCM of x2 + 5x, and x2 + 6x + 1 Factoring each: x(x+5), and (x+1)(x+5) Multiply all the factors, but use the common factor (x+5) only once: x(x+5)(x+1)



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https://math.answers.com/other-math/How_do_you_find_the_LCM_of_2_monomials

How do you find the LCM of 2 monomials? - Answers

This is similar to the often-used method to find the LCM of 2 numbers: you have to factor each monomial, and eliminate duplicate factors (factors that appear in both terms). An example might make this clearer. LCM of x2 + 5x, and x2 + 6x + 1 Factoring each: x(x+5), and (x+1)(x+5) Multiply all the factors, but use the common factor (x+5) only once: x(x+5)(x+1)

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      This is similar to the often-used method to find the LCM of 2 numbers: you have to factor each monomial, and eliminate duplicate factors (factors that appear in both terms). An example might make this clearer. LCM of x2 + 5x, and x2 + 6x + 1 Factoring each: x(x+5), and (x+1)(x+5) Multiply all the factors, but use the common factor (x+5) only once: x(x+5)(x+1)

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