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How do you find the domain and range given a quadratic function? - Answers
A quadratic function: f(x) = ax2 + bx + c = 0, where a ≠ 0. Domain: {x| x is a real number}, or in the interval notation, (-∞, ∞). Range: If a > 0, {y| y ≥ f(-b/2a), the y-coordinate of the vertex} or [f(-b/2a), ∞). If a < 0, {y| y ≤ f(-b/2a), the y-coordinate of the vertex} or (-∞, f(-b/2a)]. * * * * * Alternative answer: The domain is anything you chose it to be. For example, the integers between 2.5 and 4.7 (ie 3 and 4) and the real numbers between 4.8 and 5.0. Then the range would be the values of f(x) which corresponded to the values of x in the domain.
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How do you find the domain and range given a quadratic function? - Answers
A quadratic function: f(x) = ax2 + bx + c = 0, where a ≠ 0. Domain: {x| x is a real number}, or in the interval notation, (-∞, ∞). Range: If a > 0, {y| y ≥ f(-b/2a), the y-coordinate of the vertex} or [f(-b/2a), ∞). If a < 0, {y| y ≤ f(-b/2a), the y-coordinate of the vertex} or (-∞, f(-b/2a)]. * * * * * Alternative answer: The domain is anything you chose it to be. For example, the integers between 2.5 and 4.7 (ie 3 and 4) and the real numbers between 4.8 and 5.0. Then the range would be the values of f(x) which corresponded to the values of x in the domain.
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How do you find the domain and range given a quadratic function? - Answers
A quadratic function: f(x) = ax2 + bx + c = 0, where a ≠ 0. Domain: {x| x is a real number}, or in the interval notation, (-∞, ∞). Range: If a > 0, {y| y ≥ f(-b/2a), the y-coordinate of the vertex} or [f(-b/2a), ∞). If a < 0, {y| y ≤ f(-b/2a), the y-coordinate of the vertex} or (-∞, f(-b/2a)]. * * * * * Alternative answer: The domain is anything you chose it to be. For example, the integers between 2.5 and 4.7 (ie 3 and 4) and the real numbers between 4.8 and 5.0. Then the range would be the values of f(x) which corresponded to the values of x in the domain.
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