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How do you find the end behavior of 2x5 plus 5x4-2x3-7x2-4x-12? - Answers

f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.



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How do you find the end behavior of 2x5 plus 5x4-2x3-7x2-4x-12? - Answers

https://math.answers.com/other-math/How_do_you_find_the_end_behavior_of_2x5_plus_5x4-2x3-7x2-4x-12

f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.



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https://math.answers.com/other-math/How_do_you_find_the_end_behavior_of_2x5_plus_5x4-2x3-7x2-4x-12

How do you find the end behavior of 2x5 plus 5x4-2x3-7x2-4x-12? - Answers

f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.

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      f(x) = 2x5 + 5x4 - 2x3 - 7x2 -4x - 12 We use the Leading Coefficient Test to determine the graph's end behavior. Because the degree of f(x) is odd (n = 5) and the leading coefficient, 2, is positive, the graph falls to the left and rises to the right.

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