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How do you graph the equation y equals x minus 1? - Answers

Well that is in y intercept slope form so what you do is you make an x/y table. putting -2,-1,0,1,2 on the x axis and then multiply each of them by 1 and -1. then they form ordered pairs and you graph them! hope that helped!! An easier way to graph it would be to do this. The (x) is the slope and the (minus 1)(-1) is the y-intercept. So first you would go down one on the graph you made, (on the y-axis), and put a dot on the point (0,-1). Then by graphing the (x), you would go up 1, then right 1, up 1, right 1, and so on, until you reach the edge of the graph, and then trace a straight line through the points. Then to properly detail it, put an arrow on each end of the line. and write the equation (such as the one you graphed), above the lined equation. I Think you should get a 100% on that, your welcome



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How do you graph the equation y equals x minus 1? - Answers

https://math.answers.com/other-math/How_do_you_graph_the_equation_y_equals_x_minus_1

Well that is in y intercept slope form so what you do is you make an x/y table. putting -2,-1,0,1,2 on the x axis and then multiply each of them by 1 and -1. then they form ordered pairs and you graph them! hope that helped!! An easier way to graph it would be to do this. The (x) is the slope and the (minus 1)(-1) is the y-intercept. So first you would go down one on the graph you made, (on the y-axis), and put a dot on the point (0,-1). Then by graphing the (x), you would go up 1, then right 1, up 1, right 1, and so on, until you reach the edge of the graph, and then trace a straight line through the points. Then to properly detail it, put an arrow on each end of the line. and write the equation (such as the one you graphed), above the lined equation. I Think you should get a 100% on that, your welcome



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https://math.answers.com/other-math/How_do_you_graph_the_equation_y_equals_x_minus_1

How do you graph the equation y equals x minus 1? - Answers

Well that is in y intercept slope form so what you do is you make an x/y table. putting -2,-1,0,1,2 on the x axis and then multiply each of them by 1 and -1. then they form ordered pairs and you graph them! hope that helped!! An easier way to graph it would be to do this. The (x) is the slope and the (minus 1)(-1) is the y-intercept. So first you would go down one on the graph you made, (on the y-axis), and put a dot on the point (0,-1). Then by graphing the (x), you would go up 1, then right 1, up 1, right 1, and so on, until you reach the edge of the graph, and then trace a straight line through the points. Then to properly detail it, put an arrow on each end of the line. and write the equation (such as the one you graphed), above the lined equation. I Think you should get a 100% on that, your welcome

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      Well that is in y intercept slope form so what you do is you make an x/y table. putting -2,-1,0,1,2 on the x axis and then multiply each of them by 1 and -1. then they form ordered pairs and you graph them! hope that helped!! An easier way to graph it would be to do this. The (x) is the slope and the (minus 1)(-1) is the y-intercept. So first you would go down one on the graph you made, (on the y-axis), and put a dot on the point (0,-1). Then by graphing the (x), you would go up 1, then right 1, up 1, right 1, and so on, until you reach the edge of the graph, and then trace a straight line through the points. Then to properly detail it, put an arrow on each end of the line. and write the equation (such as the one you graphed), above the lined equation. I Think you should get a 100% on that, your welcome

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