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How do you make 77 with 4 fours? - Answers

[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4



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How do you make 77 with 4 fours? - Answers

https://math.answers.com/other-math/How_do_you_make_77_with_4_fours

[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4



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https://math.answers.com/other-math/How_do_you_make_77_with_4_fours

How do you make 77 with 4 fours? - Answers

[√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4

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      [√(4/.4*)]^4 - 4 = [√9]^4 - 4 = 3^4 - 4 = 81 - 4 = 77 N.B. the denominator within the square root is meant to be 0.4 recurring, which is written with a dot above the 4 but I am not able to do this. 0.44444...... = 4/9 Also, if you do (4-40)3 - 4

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