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https://math.answers.com/other-math/How_do_you_show_how_sin_theta_equals_cos_theta_tan_theta

How do you show how sin theta equals cos theta tan theta? - Answers

sinθ = O/H cosθ = A/H tanθ = O/A cosθ*tanθ = A/H * O/A = AO/AH = O/H Therefore, sinθ = cosθtanθ = O/H (Notes: O=opposite, A=adjacent, H=hypotenuse)



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How do you show how sin theta equals cos theta tan theta? - Answers

https://math.answers.com/other-math/How_do_you_show_how_sin_theta_equals_cos_theta_tan_theta

sinθ = O/H cosθ = A/H tanθ = O/A cosθ*tanθ = A/H * O/A = AO/AH = O/H Therefore, sinθ = cosθtanθ = O/H (Notes: O=opposite, A=adjacent, H=hypotenuse)



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https://math.answers.com/other-math/How_do_you_show_how_sin_theta_equals_cos_theta_tan_theta

How do you show how sin theta equals cos theta tan theta? - Answers

sinθ = O/H cosθ = A/H tanθ = O/A cosθ*tanθ = A/H * O/A = AO/AH = O/H Therefore, sinθ = cosθtanθ = O/H (Notes: O=opposite, A=adjacent, H=hypotenuse)

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      sinθ = O/H cosθ = A/H tanθ = O/A cosθ*tanθ = A/H * O/A = AO/AH = O/H Therefore, sinθ = cosθtanθ = O/H (Notes: O=opposite, A=adjacent, H=hypotenuse)

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