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How do you simplify the square root of 13 144? - Answers

You can simplify the term by approximation! Here is the approach: Let y = √x = x^(½). Then, dy/dx = ½ * x^(-½) = 1/(2√x) Select 115² to be x. Then, we obtain: y = 115 dy/dx = 1/(2 * 115) = 1 / 230 Therefore, we obtain this equation: y - 115 = 1/230 * (x - 115²) If x = 13144, then we have: y - 115 = 1/230 * (13144 - 115²) y = 1/230 * (13144 - 115²) + 115 ≈ 114.65 OR What you can do is to factor out each term by term and extract the perfect square factor out of the √. For instance: √(13144) = √(4 * 3286) = 2√3286



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How do you simplify the square root of 13 144? - Answers

https://math.answers.com/other-math/How_do_you_simplify_the_square_root_of_13_144

You can simplify the term by approximation! Here is the approach: Let y = √x = x^(½). Then, dy/dx = ½ * x^(-½) = 1/(2√x) Select 115² to be x. Then, we obtain: y = 115 dy/dx = 1/(2 * 115) = 1 / 230 Therefore, we obtain this equation: y - 115 = 1/230 * (x - 115²) If x = 13144, then we have: y - 115 = 1/230 * (13144 - 115²) y = 1/230 * (13144 - 115²) + 115 ≈ 114.65 OR What you can do is to factor out each term by term and extract the perfect square factor out of the √. For instance: √(13144) = √(4 * 3286) = 2√3286



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https://math.answers.com/other-math/How_do_you_simplify_the_square_root_of_13_144

How do you simplify the square root of 13 144? - Answers

You can simplify the term by approximation! Here is the approach: Let y = √x = x^(½). Then, dy/dx = ½ * x^(-½) = 1/(2√x) Select 115² to be x. Then, we obtain: y = 115 dy/dx = 1/(2 * 115) = 1 / 230 Therefore, we obtain this equation: y - 115 = 1/230 * (x - 115²) If x = 13144, then we have: y - 115 = 1/230 * (13144 - 115²) y = 1/230 * (13144 - 115²) + 115 ≈ 114.65 OR What you can do is to factor out each term by term and extract the perfect square factor out of the √. For instance: √(13144) = √(4 * 3286) = 2√3286

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      You can simplify the term by approximation! Here is the approach: Let y = √x = x^(½). Then, dy/dx = ½ * x^(-½) = 1/(2√x) Select 115² to be x. Then, we obtain: y = 115 dy/dx = 1/(2 * 115) = 1 / 230 Therefore, we obtain this equation: y - 115 = 1/230 * (x - 115²) If x = 13144, then we have: y - 115 = 1/230 * (13144 - 115²) y = 1/230 * (13144 - 115²) + 115 ≈ 114.65 OR What you can do is to factor out each term by term and extract the perfect square factor out of the √. For instance: √(13144) = √(4 * 3286) = 2√3286

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