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How do you solve 12x equals 18 mod 48? - Answers

Copied from my answer to your other question: I have changed your equation from 12x=48 mod 18 to 12x=18 mod 48 as it is impossible to have 48 mod 18 in modular arithmetic/it makes no sense. Anyway, any modular equation a=b mod m can be rewritten as a-b=km where k is an integer. or in other words, m divides a-b without remainder. Applying this to the equation above we get (12x-18)/48=k. Now just stick it into a calculator and replace x with integers or since 12 is even, a number with + 0.5 until the equation gives out an integer, in this case x turns out to be 1.5, then 5.5, 9.5 etc.



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How do you solve 12x equals 18 mod 48? - Answers

https://math.answers.com/other-math/How_do_you_solve_12x_equals_18_mod_48

Copied from my answer to your other question: I have changed your equation from 12x=48 mod 18 to 12x=18 mod 48 as it is impossible to have 48 mod 18 in modular arithmetic/it makes no sense. Anyway, any modular equation a=b mod m can be rewritten as a-b=km where k is an integer. or in other words, m divides a-b without remainder. Applying this to the equation above we get (12x-18)/48=k. Now just stick it into a calculator and replace x with integers or since 12 is even, a number with + 0.5 until the equation gives out an integer, in this case x turns out to be 1.5, then 5.5, 9.5 etc.



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https://math.answers.com/other-math/How_do_you_solve_12x_equals_18_mod_48

How do you solve 12x equals 18 mod 48? - Answers

Copied from my answer to your other question: I have changed your equation from 12x=48 mod 18 to 12x=18 mod 48 as it is impossible to have 48 mod 18 in modular arithmetic/it makes no sense. Anyway, any modular equation a=b mod m can be rewritten as a-b=km where k is an integer. or in other words, m divides a-b without remainder. Applying this to the equation above we get (12x-18)/48=k. Now just stick it into a calculator and replace x with integers or since 12 is even, a number with + 0.5 until the equation gives out an integer, in this case x turns out to be 1.5, then 5.5, 9.5 etc.

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      Copied from my answer to your other question: I have changed your equation from 12x=48 mod 18 to 12x=18 mod 48 as it is impossible to have 48 mod 18 in modular arithmetic/it makes no sense. Anyway, any modular equation a=b mod m can be rewritten as a-b=km where k is an integer. or in other words, m divides a-b without remainder. Applying this to the equation above we get (12x-18)/48=k. Now just stick it into a calculator and replace x with integers or since 12 is even, a number with + 0.5 until the equation gives out an integer, in this case x turns out to be 1.5, then 5.5, 9.5 etc.

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