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How do you solve 2 sin squared theta equals 1? - Answers

first divide each side by 2 so you get... sine^2(X)=1/2 Then make sine ^2(X)=sine(x^2) SO you get... sine(X^2)=1/2 Then take the sine^-1 of each side it will look like this X^2=sine^-1(1/2) type the right side into a calc which will give you a gross decimal but it works (0.5235987756) so now you have X^2=0.5235987756 then take the square root of each side to make it linear and you will get X=.7236012546 and that is your answer!!!! make sure to check it on your calculator...I did and it worked * * * * * Not quite correct, I fear. Try this: Let s = sin θ. Then, 2s2 = 1; s2 = ½; and s = ±½√2. Therefore, θ = 45°, 135°, 225°, or 315°; or, if you prefer, θ = ¼π, ¾π, 1¼π, or 1¾π.



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How do you solve 2 sin squared theta equals 1? - Answers

https://math.answers.com/other-math/How_do_you_solve_2_sin_squared_theta_equals_1

first divide each side by 2 so you get... sine^2(X)=1/2 Then make sine ^2(X)=sine(x^2) SO you get... sine(X^2)=1/2 Then take the sine^-1 of each side it will look like this X^2=sine^-1(1/2) type the right side into a calc which will give you a gross decimal but it works (0.5235987756) so now you have X^2=0.5235987756 then take the square root of each side to make it linear and you will get X=.7236012546 and that is your answer!!!! make sure to check it on your calculator...I did and it worked * * * * * Not quite correct, I fear. Try this: Let s = sin θ. Then, 2s2 = 1; s2 = ½; and s = ±½√2. Therefore, θ = 45°, 135°, 225°, or 315°; or, if you prefer, θ = ¼π, ¾π, 1¼π, or 1¾π.



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https://math.answers.com/other-math/How_do_you_solve_2_sin_squared_theta_equals_1

How do you solve 2 sin squared theta equals 1? - Answers

first divide each side by 2 so you get... sine^2(X)=1/2 Then make sine ^2(X)=sine(x^2) SO you get... sine(X^2)=1/2 Then take the sine^-1 of each side it will look like this X^2=sine^-1(1/2) type the right side into a calc which will give you a gross decimal but it works (0.5235987756) so now you have X^2=0.5235987756 then take the square root of each side to make it linear and you will get X=.7236012546 and that is your answer!!!! make sure to check it on your calculator...I did and it worked * * * * * Not quite correct, I fear. Try this: Let s = sin θ. Then, 2s2 = 1; s2 = ½; and s = ±½√2. Therefore, θ = 45°, 135°, 225°, or 315°; or, if you prefer, θ = ¼π, ¾π, 1¼π, or 1¾π.

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      first divide each side by 2 so you get... sine^2(X)=1/2 Then make sine ^2(X)=sine(x^2) SO you get... sine(X^2)=1/2 Then take the sine^-1 of each side it will look like this X^2=sine^-1(1/2) type the right side into a calc which will give you a gross decimal but it works (0.5235987756) so now you have X^2=0.5235987756 then take the square root of each side to make it linear and you will get X=.7236012546 and that is your answer!!!! make sure to check it on your calculator...I did and it worked * * * * * Not quite correct, I fear. Try this: Let s = sin θ. Then, 2s2 = 1; s2 = ½; and s = ±½√2. Therefore, θ = 45°, 135°, 225°, or 315°; or, if you prefer, θ = ¼π, ¾π, 1¼π, or 1¾π.
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