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How do you write 3559028982 in expanded form with exponents? - Answers
Expanded Notation of 3,559,028,982 = (3 x 10^9) + (5 x 10^8) + (5 x 10^7) + (9 x 10^6) + (0 x 10^5) + (2 x 10^4) + (8 x 10^3) + (9 x 10^2) + (8 x 10^1) + (2 x 10^0) To answer this question count the number of digits in this number before the decimal point. There are 10. Therefore, in this number, the leftmost digit will be a multiple of 10 to the power of 9 (1 less than the number of digits before the decimal point). Working from left to right, each successive digit is a multiple of 10 to the power of 1 less than the digit before. So, we can write this as:
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How do you write 3559028982 in expanded form with exponents? - Answers
Expanded Notation of 3,559,028,982 = (3 x 10^9) + (5 x 10^8) + (5 x 10^7) + (9 x 10^6) + (0 x 10^5) + (2 x 10^4) + (8 x 10^3) + (9 x 10^2) + (8 x 10^1) + (2 x 10^0) To answer this question count the number of digits in this number before the decimal point. There are 10. Therefore, in this number, the leftmost digit will be a multiple of 10 to the power of 9 (1 less than the number of digits before the decimal point). Working from left to right, each successive digit is a multiple of 10 to the power of 1 less than the digit before. So, we can write this as:
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How do you write 3559028982 in expanded form with exponents? - Answers
Expanded Notation of 3,559,028,982 = (3 x 10^9) + (5 x 10^8) + (5 x 10^7) + (9 x 10^6) + (0 x 10^5) + (2 x 10^4) + (8 x 10^3) + (9 x 10^2) + (8 x 10^1) + (2 x 10^0) To answer this question count the number of digits in this number before the decimal point. There are 10. Therefore, in this number, the leftmost digit will be a multiple of 10 to the power of 9 (1 less than the number of digits before the decimal point). Working from left to right, each successive digit is a multiple of 10 to the power of 1 less than the digit before. So, we can write this as:
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- og:descriptionExpanded Notation of 3,559,028,982 = (3 x 10^9) + (5 x 10^8) + (5 x 10^7) + (9 x 10^6) + (0 x 10^5) + (2 x 10^4) + (8 x 10^3) + (9 x 10^2) + (8 x 10^1) + (2 x 10^0) To answer this question count the number of digits in this number before the decimal point. There are 10. Therefore, in this number, the leftmost digit will be a multiple of 10 to the power of 9 (1 less than the number of digits before the decimal point). Working from left to right, each successive digit is a multiple of 10 to the power of 1 less than the digit before. So, we can write this as:
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