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How many Sides does a polygon have with 140 degree angles? - Answers

The sum of the angles : (n - 2)180° The measure of one angle: [(n - 2)180°]/n Then we have: [(n - 2)180°]/n = 140° multiply by n to both sides; [(n - 2)180°] = 140°n 180°n - 360° = 140°n divide by 20 to both sides; 9°n - 18° = 7°n subtract 7°n and add 18° to both sides; 2°n = 18° divide by 2° to both sides; n = 9 Thus, the regular polygon has 9 sides.



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How many Sides does a polygon have with 140 degree angles? - Answers

https://math.answers.com/other-math/How_many_Sides_does_a_polygon_have_with_140_degree_angles

The sum of the angles : (n - 2)180° The measure of one angle: [(n - 2)180°]/n Then we have: [(n - 2)180°]/n = 140° multiply by n to both sides; [(n - 2)180°] = 140°n 180°n - 360° = 140°n divide by 20 to both sides; 9°n - 18° = 7°n subtract 7°n and add 18° to both sides; 2°n = 18° divide by 2° to both sides; n = 9 Thus, the regular polygon has 9 sides.



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https://math.answers.com/other-math/How_many_Sides_does_a_polygon_have_with_140_degree_angles

How many Sides does a polygon have with 140 degree angles? - Answers

The sum of the angles : (n - 2)180° The measure of one angle: [(n - 2)180°]/n Then we have: [(n - 2)180°]/n = 140° multiply by n to both sides; [(n - 2)180°] = 140°n 180°n - 360° = 140°n divide by 20 to both sides; 9°n - 18° = 7°n subtract 7°n and add 18° to both sides; 2°n = 18° divide by 2° to both sides; n = 9 Thus, the regular polygon has 9 sides.

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      The sum of the angles : (n - 2)180° The measure of one angle: [(n - 2)180°]/n Then we have: [(n - 2)180°]/n = 140° multiply by n to both sides; [(n - 2)180°] = 140°n 180°n - 360° = 140°n divide by 20 to both sides; 9°n - 18° = 7°n subtract 7°n and add 18° to both sides; 2°n = 18° divide by 2° to both sides; n = 9 Thus, the regular polygon has 9 sides.

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