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Derivative of 3cos²x sin x? - Answers

To find the derivative of ( y = 3\cos^2 x \sin x ), we use the product rule and the chain rule. The derivative is given by: [ \frac{dy}{dx} = 3\left(-2\cos x \sin x \sin x + \cos^2 x \cos x\right) ] Simplifying this gives: [ \frac{dy}{dx} = 3\cos^2 x \cos x - 6\cos x \sin^2 x = 3\cos x (\cos^2 x - 2\sin^2 x) ]



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Derivative of 3cos²x sin x? - Answers

https://math.answers.com/math-and-arithmetic/Derivative_of_3cos%C2%B2x_sin_x

To find the derivative of ( y = 3\cos^2 x \sin x ), we use the product rule and the chain rule. The derivative is given by: [ \frac{dy}{dx} = 3\left(-2\cos x \sin x \sin x + \cos^2 x \cos x\right) ] Simplifying this gives: [ \frac{dy}{dx} = 3\cos^2 x \cos x - 6\cos x \sin^2 x = 3\cos x (\cos^2 x - 2\sin^2 x) ]



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https://math.answers.com/math-and-arithmetic/Derivative_of_3cos%C2%B2x_sin_x

Derivative of 3cos²x sin x? - Answers

To find the derivative of ( y = 3\cos^2 x \sin x ), we use the product rule and the chain rule. The derivative is given by: [ \frac{dy}{dx} = 3\left(-2\cos x \sin x \sin x + \cos^2 x \cos x\right) ] Simplifying this gives: [ \frac{dy}{dx} = 3\cos^2 x \cos x - 6\cos x \sin^2 x = 3\cos x (\cos^2 x - 2\sin^2 x) ]

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      To find the derivative of ( y = 3\cos^2 x \sin x ), we use the product rule and the chain rule. The derivative is given by: [ \frac{dy}{dx} = 3\left(-2\cos x \sin x \sin x + \cos^2 x \cos x\right) ] Simplifying this gives: [ \frac{dy}{dx} = 3\cos^2 x \cos x - 6\cos x \sin^2 x = 3\cos x (\cos^2 x - 2\sin^2 x) ]

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