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How do you divide 30 into 3 odd numbers? - Answers

To divide 30 into 3 odd numbers, we can use the formula for the sum of an arithmetic series: (S_n = \frac{n}{2}(a_1 + a_n)), where (S_n) is the sum of the series, (n) is the number of terms, (a_1) is the first term, and (a_n) is the last term. Since we want 3 odd numbers, we can let the first odd number be 1, the second odd number be 3, and the third odd number be 5. Thus, the sum of the series is (S_3 = \frac{3}{2}(1 + 5) = 3 \times 3 = 9). Since 9 is less than 30, we can conclude that it is not possible to divide 30 into 3 odd numbers.



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How do you divide 30 into 3 odd numbers? - Answers

https://math.answers.com/other-math/How_do_you_divide_30_into_3_odd_numbers

To divide 30 into 3 odd numbers, we can use the formula for the sum of an arithmetic series: (S_n = \frac{n}{2}(a_1 + a_n)), where (S_n) is the sum of the series, (n) is the number of terms, (a_1) is the first term, and (a_n) is the last term. Since we want 3 odd numbers, we can let the first odd number be 1, the second odd number be 3, and the third odd number be 5. Thus, the sum of the series is (S_3 = \frac{3}{2}(1 + 5) = 3 \times 3 = 9). Since 9 is less than 30, we can conclude that it is not possible to divide 30 into 3 odd numbers.



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https://math.answers.com/other-math/How_do_you_divide_30_into_3_odd_numbers

How do you divide 30 into 3 odd numbers? - Answers

To divide 30 into 3 odd numbers, we can use the formula for the sum of an arithmetic series: (S_n = \frac{n}{2}(a_1 + a_n)), where (S_n) is the sum of the series, (n) is the number of terms, (a_1) is the first term, and (a_n) is the last term. Since we want 3 odd numbers, we can let the first odd number be 1, the second odd number be 3, and the third odd number be 5. Thus, the sum of the series is (S_3 = \frac{3}{2}(1 + 5) = 3 \times 3 = 9). Since 9 is less than 30, we can conclude that it is not possible to divide 30 into 3 odd numbers.

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      To divide 30 into 3 odd numbers, we can use the formula for the sum of an arithmetic series: (S_n = \frac{n}{2}(a_1 + a_n)), where (S_n) is the sum of the series, (n) is the number of terms, (a_1) is the first term, and (a_n) is the last term. Since we want 3 odd numbers, we can let the first odd number be 1, the second odd number be 3, and the third odd number be 5. Thus, the sum of the series is (S_3 = \frac{3}{2}(1 + 5) = 3 \times 3 = 9). Since 9 is less than 30, we can conclude that it is not possible to divide 30 into 3 odd numbers.
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